Question

10. The sum and product of the zeroes of the polynomial ×2-6×+ 8 are respectively
A: -3/2 and -1
B: 6 and 8
C-3/2 and 1
D: 3/2 and 1​

Answer 1

Answer:

B] 6 and 8

Method 1:

Given Quadratic equation → x² - 6x + 8

First let's find out the zeroes of the polynomial. In order to do this, we need to factorise the polynomial by splitting the middle term.

x² - 6x + 8 = 0

→ x² - 2x - 4x + 8 = 0

→ x (x - 2) - 4 (x - 2) = 0

→ (x - 2) (x - 4) = 0

So,

• (x - 2) = 0 ⇒ x = 2
• (x - 4) = 0 ⇒ x = 4

So, the zeroes are 2 and 4

Now find the sum of zeroes.

Sum of zeroes = 2 + 4 = 6

Then the product of zeroes.

Product of zeroes = 2(4) = 8

Therefore,

• Sum of zeroes = 6
• Product of zeroes = 8

Method 2:

Sum of zeroes = -b ÷ a

⇒ Sum of zeroes = -(-6) ÷ 1

⇒ Sum of zeroes = 6

Product of zeroes = c ÷ a

⇒ Product of zeroes = 8 ÷ 1

⇒ Product of zeroes = 8