10. The sum of three consecutive integers is 5 more than the smallest of the integers. Find the
integers.
Answers
Answered by
2
Hi friend here is ur answer,
Let the smallest integer be x
Then according to question,
=> x + x + 1 + x + 2 = x + 5
=> 3x + 3 = x + 5
=> 3x - x = 5 - 3
=> 2x = 2
=> x = 1
The integers are-
x = 1
x + 1= 1+1 =2
x +2= 1+2=3
Hope it helps you
Let the smallest integer be x
Then according to question,
=> x + x + 1 + x + 2 = x + 5
=> 3x + 3 = x + 5
=> 3x - x = 5 - 3
=> 2x = 2
=> x = 1
The integers are-
x = 1
x + 1= 1+1 =2
x +2= 1+2=3
Hope it helps you
Answered by
2
Let us assume, the three consecutive integers are n, n+1 and n+2, where n is a positive integer
Given:
n + n + 1 + n + 2 = n + 5
3n + 3 = n + 5
2n = 2
n = 1
Therefore, the three consecutive intergers are 1, 2 and 3
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