Math, asked by cristy63, 8 months ago

(10) The temperature of a rod was 10°C above zero. It was kept in a freezer at 2 p.m. If its temperature
decreased at the rate of 3°C per minute, at what time would the temperature be 8°C below zero? And
what would be the temperature at 2:15 p.m.?

Answers

Answered by venkatarajesh75
5

Answer:

Happy Raksha bandhan

The temperature of rod was 10 degrees celsius  above 0 means = 0 + 10 = 10degrees celsius.

Rate of temperature decreasing - 3 degrees celsius / per minute [ 1 degree celsius / 20 secs ]

Time it was kept in freezer - 2 p.m.

Time the temperature will decrease to 8 degrees celsisus.

Foe every minute the temperature will decease 3 degrees celsius , here it only decreased to 8 degrees celsius , decreased 2 degrees celsius ;

That means it has been less than a minute ;

So , it has been decreased 2 degrees celsius [ Rate of decreasing - 1 degree celsius / 20 secs ]

So , it has been 2x 20 secs = 40 secs. That means ,   The time would be exactly 2 : 00 : 40 PM

Temperature for the time 2:15 PM ; 15 minutes done after placing it in the freezer ; [ Rate of decreasing 3 degrees celsius / per minute ]

15 minutes done = 15 min x 3 = 45 degrees celsius  increased ; Means 10 degrees celsius - 45 degrees celsius = -35  degrees celsius.

Therefore the temperature of the rod was -35 degrees at the time of  2:15PM .

Answered by ItzAaryan
2

Below 8°C from zero in 6 minutes

On 2:15 pm it is -35°C

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