10. The upper part of a tree broken by wind, falls to the ground without being detached.
The top of the broken part touches the ground at an angle of 38° 30' at a point 6 m
from the foot of the tree. Calculate :
(i) the height at which the tree is broken.
(ii) the original height of the tree correct to two decimal places.
Answers
Answered by
2
Consider
TR as the height of the tree,
TP as the broken part which touches the ground at a distance of 6m from the foot of the tree which makes an angle of 38o30′ with the ground.
Take PR=x and PQ=PT=y
Thus, TR=x+y
In right triangle PQR,
tanθ=QRPR
Substituting the values,
⇒tan38o30′=6x
⇒0.7954=6x
⇒x=0.7954×6=4.7724
sinθ=PQPR
Substituting the values,
⇒sin38o30′=yx
⇒
Answered by
5
Step-by-step explanation:
Take PR=x and PQ=PT=y
Thus, TR=x+y
In right triangle PQR,
tanθ=
QR
PR
Substituting the values,
⇒tan38
o
30
′
=
6
x
⇒0.7954=
6
x
⇒x=0.7954×6=4.7724
sinθ=
PQ
PR
Substituting the values,
⇒sin38
o
30
′
=
y
x
⇒0.6225=
y
4.7724
⇒y=
0.6225
4.7724
=7.6665
Hence,
Height of the tree =4.7724+7.6665=12.4389=12.44 m.
Height of the tree at which it is broken =4.77 m.
solution
hope it's help you dear.....
please mark me in brainlist and also follow me plzz...
Attachments:
Similar questions