Question

10 The vapour pressure of a pure liquid is 0.043 bar
at certain temperature. When a non-volatile solutes
dissolved into it, the vapour pressure of the solution is
found to be 0.041 bar. What is the relative lowering
vapour pressure .​

Answer 1

Answer:

Explanation:

Given- P1⁰= 0.043

P1 = 0.041

To find- Relative Lowering of vapour pressure

Formula- ∆P/ P1⁰= P1⁰- P1 / P1⁰

Solution- ∆P/P1=P1⁰-P1 / P1⁰= 0.043-0.041/0.043 = 0.0465