10. there is a circle with centre O and diameter AB.
(1) Find angle APB.
(ii) If A = angle 60°, find angle B.
(iii) IF AP = 5 cm and PB = 12 cm, find AB and radius of
circle.
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As AB is diameter, any angle in semicircle will be 90 degree
therefore, angle APB =90 degree.
in triangle APB,
Measure of angle A+measure of angle B+measure of angle P=180 degree.
therefore,
60+measure of angle B+90=180
150+measure of angle B=180
measure of angle B=180-150
therefore, measure of angle B=30 degree.
5,12and 13 is Pythagorean triplet.
therefore,AB=13.
radius=2 X diameter.
therefore, radius of circle=6.5 cm
I hope it helps you
Answered by
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Answer:
the answer are below
Step-by-step explanation:
1)90°
as, angle inside a semicircle touching the arc and one side is the diameter is an right angle
2)30°
as,sum of all angles of an triangle is equal to 180°
3)13cm
by pythagoras theorem
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