Question

10. There was 60 ml of water in Beaker A and 100 ml of water in Beaker B.
(a) Find the ratio of the volume of water in Beaker A to the volume of water in
Beaker B.
(b) After some water was added to both beakers, Beaker A had 90 ml of water
The ratio of the volumes of water in both beakers remained the same. How
much water was added to Beaker B?

Answer 1

Answer:

beaker A = 60 ml water

beaker B= 100 ml water

a)

ratio= A:B

=60:100 = 6:10 =3:5

b)

beaker A = 90 ml

total water =

90×8/3=240

beaker B=

=240/8×5=150