English, asked by pihusingh21, 4 months ago


10) Three metal cubes with edges 6 cm, 8 cm and 10 cm respectively are
melted and formed into a single cube. Find the diagonal of this cube.​

Answers

Answered by TheFairyTale
23

AnswEr :

  • 12√3 cm

GivEn :

  • Three metal cubes with edges 6 cm, 8 cm and 10 cm respectively are
  • melted.
  • They are formed into a single cube.

To Find :

  • The diagonal of new cube.

Solution :

The formula of volume of cubes,

 \boxed{ \sf{V_{cube} =  {a}^{3} }}

  • a = Side of cube

Melting the cubes, we get the total volume of new cube.

  • Volume of 1st cube = 6³ = 216 cm³
  • Volume of 2nd cube = 8³ = 512 cm³
  • Volume of 3rd cube = 10³ = 1000 cm³

Total volume = 216 + 512 + 1000 = 1728 cm³

Now, the side of new cube,

  • a³ = 1728
  • → a = 12

Therefore, the diagonal is (a√3) = 12√3 cm.

Answered by Anonymous
8

\huge\bold{\mathbb{QUESTION}}

Three metal cubes with edges 6\:cm, 8\:cm and 10\:cm respectively are melted and formed into a single cube. Find the diagonal of this cube.

\huge\bold{\mathbb{GIVEN}}

  • Three metal cubes with edges 6\:cm, 8\:cm and 10\:cm respectively are melted and formed into a single cube.

\huge\bold{\mathbb{TO\:FIND}}

The diagonal of the cube.

\huge\bold{\mathbb{SOLUTION}}

We know that:

\boxed{\boxed{Volume_{(Cube)}=a^3\:unit^3}}

Where, a is the side of the cube.

Putting the formula, let's find out the volume of each cube.

Volume of:

  • 1^{st} cube =a^3=6^3\:cm^3=216\:cm^3

  • 2^{nd} cube =a^3=8^3\:cm^3=512\:cm^3

  • 3^{rd} cube =a^3=10^3\:cm^3=1000\:cm^3

Volume of the new cube

= V_{(1st\:cube)}+V_{(2nd\:cube)}+V_{(3rd\:cube)}

= (216+512+1000)\:cm^3

= 1728\:cm^3

Using the formula, let's find out the side of the new cube.

a^3=1728

\implies a=\sqrt[3]{1728}

\implies a=\sqrt[3]{(12\times12\times12)}

\implies a=12

So, side of the new cube =12\:cm

We know that:

\boxed{\boxed{Diagonal_{(Cube)}=\sqrt{3}a\:unit}}

Where, a is the side of the cube.

Putting the formula, let's find out the diagonal of the cube.

\sqrt{3}a

=\sqrt{3}\times12

=12\sqrt{3}

So, diagonal of the new cube =12\sqrt{3}\:cm

\huge\bold{\mathbb{THEREFORE}}

The diagonal of the new cube is 12\sqrt{3}\:cm.

\huge\bold{\mathbb{WE\:MADE\:IT\:!!}}

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