10. Tickets numbered 2, 3, 4, 5, .....100, 101 are placed in a box and mixed thoroughly. One ticket is
drawn at random from the box. Find the probability that the number on the ticket is
a). a two-digit number
b). a perfect square number
c). a number divisible by 5.
d), a number divisible by 2 or 3.
e). a number divisible by 2 and 3.
f). a number divisible by 7.
g). a number multiple of 8.
h). a two digit number divisible by 5.
i). a two digit number divisible by 2.
j). a two digit number divisible by 3.
plz.z...answer this I'll mark u as brainlyest......plz..
Answers
Answer:
total outcomes = 100
a) favourable outcomes = {10, 11,12.......99}
= 90
probability of a two digit number = 90/100
= 9/10
b) favourable outcomes = {4,9,16,25,36,49, 64 ,81,100}
= 9
probability = 9/100
c) favourable outcomes = 20
prowebability = 20/100
= 1/5
d) a number divisible by 2 = 50 nos.
probability 1 = 50/100
= 1/2
a number divisible by 3 = 33
probability 2 = 33/100
probability ( divisible by 2 or 3 ) = 50/100+33/100
= 83/100
e) a number divisible by both 2 and 3 = 50/100×33/100
= 165/10000
f) favourable outcomes = 14
probability = 14/100
= 7/50
g) favourable outcomes = 12
probability = 12/100
= 6/50
= 3/25
h) favourable outcomes = { 10, 15, 20 ,...... 95}
= 18
probability = 18/100
= 9/50
i ) favourable outcomes = { 10,12, 14,16.......98}
=45
probability = 45/100
= 9/50
j) favourable outcomes = {12,15,18.....99}
= 30
probability = 30/100
= 3/10
hope it helps and mark me as the brainliest
The number of cards between 2 to 101 is 100.
a) a two-digit number = 92/100 = 23/25
b). a perfect square number = 9/100
c). a number divisible by 5.= 20/100 = 1/5
d), a number divisible by 2 or 3.= 83/100
e). a number divisible by 2 and 3 = 16/100 = 4/25
f). a number divisible by 7 = 14/100 = 7/50
g). a number multiple of 8 = 12/100 = 3/25
h). a two digit number divisible by 5 = 19/100
i). a two digit number divisible by 2 = 46/100 = 23/50
j). a two digit number divisible by 3 = 30/100 = 3/10
Thank u.
Hope this helps you.
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@spyder