Question

10 to the power 16 electrons pass from a point a to point B in 1 second in a conductor what is the magnitude of current and what is the direction give that charge on each electron e= 1.6 into 10 to the power minus 19 c​

Answer 1

Answer:

1.6×10^-3A

Explanation:

since current(I) = charge(Q)/time take(t),

here total charge = 1.6×10^-19 × 10^¹⁶ = 1.6×10^-3

given time taken = 1 second

using these values we get,

I = 1.6×10^-3/1 = 1.6×10^-3A.

In case I am wrong please correct me. Thank you