Question

10. Two adjacent angles of a parallelogram are (3x – 4)0 and (3x + 16)0. Find the value of x and hence find the measure of each of its angles​

Answer 1

Answer:

The sum of two adjacent angles of a parallelogram =180°

(3x-4)°+(3x+16)°=180°

3x-4+3x+16=180°

6x+12=180°

{take out the common )

6(x+2)=180°

x+2=180÷6

x+2=30

x=30-2

x=28

Thus, putting the value of x

(3x-4)°=3×28-4 =80°

(3x+16)°=3×28+16 =100°