Question

10.Two capacitors C; (12u f) and C2 (24 uf) are in series
connected across a 360 volts d.c. supply. Calculate the charges on C1 and C2.​

Answer 1

Answer:

The equivalent capacitance is C

eq

=

C

1

+C

2

C

1

C

2

=

2+8

2×8

=1.6μF.

Equivalent charge is Q

eq

=C

eq

V=1.6×10

−6

×300=4.8×10

−4

C

As the capacitors are in series so charge on each capacitor is Q

eq

=4.8×10

−4

C.

The potential difference across C

1

is V

1

=

C

1

Q

eq

=

2×10

−6

4.8×10

−4

=240V

The potential difference across C

2

is V

2

=

C

2

Q

eq

=

8×10

−6

4.8×10

−4

=60V

Energy stored in the system is U=

2

1

C

eq

V

2

=

2

1

×1.6×10

−6

×(300)

2

=7.2×10

−2

J