Math, asked by mantrapatel111206, 2 months ago

10. Two dice are tossed together write all possible outcomes of this experiment. Find the probability
of getting
(i) 7 as the sum
(ii) a sum greater than 10.
(ii) a sum less than 13.​

Answers

Answered by rohan310806
17

Sample space for total number of possible outcomes

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total number of outcomes =36

Favorable outcomes for sum greater than 10 are

(5,6),(6,5),(6,6)

Number of favorable outcomes =3

Favorable outcomes for sum less than 5 are

(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)

Number of favorable outcomes =6

Hence, the probability of obtaining a sum greater than 10 or sum less than 5 =

36

3+6

=

4

1

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