Question

10. Two equal sides of an isoscles triangle are each 2 cm more than thrice the third side,
the perimeter of triangle is 67 cm, find the lengths of its sides.
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Answer 1

Answer:

21 , 23, 23

Step-by-step explanation:

Take the 3rd side as x and both same sides as (x+2) and simplify

x+(x+2)+(x+2)= 63

Answer 2

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Given

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• Perimeter of triangle = 67cm

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To Find

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• Length of sides of triangle

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Solution

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Let the third side be x.

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So, other two sides are 3x + 2

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According to question,

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$\bf \implies Perimeter \: of △ = 67cm$

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$\bf \implies x + 3x + 2 + 3x + 2 = 67$

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$\bf \implies7x + 4 = 67$

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$\bf \implies7x = 67 - 4$

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$\bf \implies7x = 63$

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$\bf \implies x = 63 \div 7$

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$\bf \implies x = 9cm$

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Therefore, third side = x = 9cm

and other two sides = 3x + 2 = 3×9+2 = 29cm

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Hence, sides of triangle are 9cm, 29cm and 29cm.