Question

10. Two equal sides of an isoscles triangle are each 2 cm more than thrice the third side
the perimeter of triangle is 67 cm, find the lengths of its sides.
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Answer 1

let each side be x

one equal side = 3x + 2

(3x + 2) x 2 + x = 67

7x + 4 = 67

7x = 67 - 4 = 63

x = 63 / 7 = 9

equal side = 3 x 9 + 2 = 27 + 2 = 29  

third side = 9