10. Two metallic oxides contain 27.6% and 30% oxygen respectively. If the formula of the first oxide is X204, that of the second will be xo , that of the second one of he is one (1) XO (2) XO (3) X205 (4) X2O3
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Answer:
MARK BRAINLIEST
Explanation:
Given that, the formula of first oxide =M
3
O4
Let mass of the metal = x
% of metal in M
3
O
4
=(3x/3x+64)×100
But as given percentage = (100-27.6) = 72.4 %
so, (3x/3x+64)×100=72.4
or x = 56.
In 2nd oxide,
oxygen = 30%....so metal = 70%
so, the ratio is
M : O
70/56 : 30/16
1.25: 1.875
2 : 3
so, 2nd oxide is M
2
O
3
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