10. two students appeared at an examination. one of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. the marks obtained by them are:
Answers
Answered by
10
Let the marks of student 1 = x
marks of student 2 will be = x+9
Now marks of student 2 = 56% of sum of marks of (student 1 and student 2)
=> x+9 = 56% of ( x + x+9)
=> x+9 = 56/100 ( 2x + 9)
=> 100x + 900 = 112x + 504
=> 112x - 100x = 900 - 504
=> 12x = 396
=> x = 396/12
=> x = 33
so marks of student 1 = 33
marks of student 2 = 33 + 9 = 42
marks obtained by them are 33 and 42
Answered by
5
Answer:
33 and 42
Step-by-step explanation:
Let one of the student secure x Marks
the other student secures (x+9)
From the given condition, we have
(x+9)=56percent of (x+x+9)=56/100×(2x+9)
100x+900=112x+504
12x=900-504
x=396/12
x=33
Therefore,Marks obtained by first student =33
Marks obtained by other student =42
Similar questions