Question

10. Urn A contains 2 white, 1 black and 3 red balls, urn B contains 3 white, 2 black and 4 red balls and
urn C contains 4 white, 3 black and 2 red balls. One urn is chosen at random and 2 balls are drawn
at random from the urn. If the chosen balls happen to be red and black, what is the probability that
both balls come from urn B?​

Answer 1

Answer:

Find : chance of chosen second urn ( multiply ) probablity of selecting red and black balls

Ans :

first step chance of chose second urn is = 1/3

second step find the way of chose red and black ball ( 4 red + 2 black )

there is way of selection is ⁴c1× ²c1 = 8

total way of selection is ⁹c2 = 36

final answer :

=1/3 × 8/36

= 8 / 108

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