Question

10. Using remainder theorem, find the remainder when x^3 – 6x^2 + 2x – 4 is divided by x + 1. Check your answer by actual division.

Answer 1

$\sf Since,~ x^3 – 6x^2 + 2x – 4~ is ~divisible~ by ~x+1 \\\\\sf x+1=0 \\\\\sf => x= - 1 \\\\\sf </p><p>Putting ~the~ value~ of ~x~ = ~- 1 ~in ~ x^3 – 6x^2 + 2x – 4 \\\\\sf = (-1)^3-6(-1)^2+2(-1) - 4 \\\\\sf = - 1-6-2-4 \\\\\sf - 13$

Hence, remainder is - 13

Answer 2

Answer:

234566799986523467890974

Step-by-step explanation:

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