Question

10) Vapour pressure of water at 25 oC is 24 mmHg. In a solution of 0.2 m glucose the vapour pressure is found to be 23.90 mmHg. Calculate the activity and activity coefficient of water in the solution. Comment on the nature of the solution.​

Answer 1

Step-by-step explanation:

Let us consider the problem:

Given that:

W=5g,WA=95g,MB=60.05gmol−1

MA=18gmol−1,P0A=3.165kPa

Putting the values in expression

PAoPAo−P=MB×WAWB×MA

3.165kPa3.165kPa−P=60.05gmol−1×95g5g×18gmol−1=0.015

Hence,

P=3.165kPa−0.015×3.165kPa

P=3.118kPa.