Question

10. Verify(a-b)(a+b)+(b-c)(b+c)+(c-a) (c+a)=0
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Answer 1

Answer:

We know that,

(x-y) (x+y) =x²-y²

Therefore, putting in the LHS.

a²-b² + b²-c²+c²-a²

=0

=RHS

HP

Answer 2

Answer:

here is your answer......

Step-by-step explanation:

as we know that ,

a^2 -b^2 = (a+b)(a-b)

therefore,

a^2 - b^2 + b^2 - c^2 + c^2 - a^2

0 which is equal to R.H.S