Question

10. What is the power consumed by bulb from above circuit ? F (A) 23V 2A​

Answer 1

Answer:

Explanation:

V=23v

i=2a

p=vi

23*2

46

Answer 2

Answer:

Power = force multiplied by speed (velocity) p=F xv.

To so answer will be 46

find the kilowatt-hours your light bulb consumes per month, multiply the kilowatt use by the number of hours it's on each month. The incandescent bulb uses 0.06 kW of power and is on for 180 hours a month.

Explanation:

P = V2 / R = 1002 / 193.6 = 62.5 Watts. This is the total power consumed by both bulbs. Since both bulbs have the same resistance, each consumes half of that power, or 31.25 Watts

The power dissipated in each bulb is either (1/9)2 × 360 = 4.44 watts, or (1/9) × 40 = 4.44 watts. The total power dissipated in the circuit is three times this, or 13.3 watts ((1/9)2 × 3(360) = 1080/81 = 13.3 W, or (1/9) A × 120 V = 13.3 W)

Thank you.