Question

10. What is the smallest number that, when divided by 35, 56 and 91 leaves remainders
7 in each case.
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Answer 1

Answer:

3647 is the smallest number

Answer 2

Hello..

The smallest number which when divided by 35, 56 and 91 = LCM of (35,56,91)

• (35,56,91)35=5×7

• 56=2³ × 7

• 91=7×13

• LCM=2³ ×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

So, your answer is 3647

This helps you..Any doubt? ask me through comments..