Question

10. When R, R, and R, are connected in series then what will be the resultant
resistance R of the combination ?​

Answer 1

Answer:

Answer would be n2x.

1/Re=1/r +1/r +1/r...n/r

1/Re= n/r (in case of parallel)

Re=r/n ----> x=r/n

r=xn

so now in case of series

it would be n2 times of resultant resistance x.

Re= r+r+.....nr

Re=nr (as r=xn)

so,

Re=n×xn

Re=n2x

Answer 2

ANSWER

HEY MATE

It is given that, resistance of n wires each of resistance r ohm is R when they are connected in parallel. So,

r1 + rr+ 11

........ntimes=

R

1r

n = R1

r=nR..........(1)

When resistors are connected in series, the equivalent resistance will be,

r+r+r+r...........ntimes=nr

=n(nR)=n

2

R

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