Question

10. When the electron of 'H' atom jumps from n =4 to n = 1 state, the no.of spectral lines emitted is
a) 15
b) 9
d)3
c) 16
​

Answer 1

formula for calculating no. of spectral lines =

N

$= \frac{(n2 - n1)(n2 - n1 + 1)}{2}$

we have n2= 4 and n1 = 1

so, putting in formula

$\frac{(4 - 1)(4 - 1 + 1)}{2} = \frac{3 \times 3 + 1}{2} = \frac{3 \times 4}{2} = \frac{12}{2 } = 6$

so the no. of spectral lines is equal to 6

mark as brainliest