Question

10. Which term of the GP 2,2√2,4......
is 64
​

Answer 1

1st term= 2....r=

$2 \sqrt{2} \div 2$

so....r= $\sqrt{2}$

64=a* r^(n-1)

or.....64= 2* $\sqrt{2}$^(n-1)

or. 32= ${2}{((n-1)/2)}$

or....2^5=2^((n-1)/2)

since bases are same....

5=(n-1)/2

or n= $\textbf{11}$

$\textbf{so ans is 11th term}$

hope itt helps....

plz mark brainliest