Question

10. Without using tables solve each of the following
triangles ABC, right-angled at C; given
(i) A = 30° and c = 40;
(ii) B = 60° and c= 15;
(iii) A = 45° and a = 7.​

Answer 1

Answer:

We have,

∠A = 30°

∠C = 90°

AB = 40 Units.

∠A + ∠B + ∠C = 180°

30° + ∠B + 90° = 180°

∠B = 180° - 120°

∠B = 60°

Cos A = adjacent / hypotenuse ⇒ AC/AB

Cos 30° = AC/40

√3/2 = AC/40

AC = √3/2 × 40

AC = 20√3 Units.

And,

Sin A = Opposite / Hypotenuse ⇒ BC/AB

Sin 30° = BC/40

1/2 = BC/40

BC = 40×1/2

BC = 20 Units.

Hence, AC = 20√3 Units,

BC = 20 Units

And

∠B = 60°.

Answer 2

Answer:

this is the answer so please write and say me I have done wrong or not