Question

10. Write a pair of fractions whose sum is 7/11 and difference is 2/11

Answer 1

Answer:

Let the fractions be a/b and x/y

According to question

a/b + x/y = 7 / 11 ------(1)

a/b - x/y = 2 / 11 -------(2)

On adding equation 1 and 2, we get

2× a/b = ( 7 + 2) / 11

=> a/b = 9 / 22

Now,

On substituting the value of a/b in equation 1, we get

9 / 22 + x/y = 7 / 11

=> x/y = 7 / 11 - 9 / 22

=> x/y = ( 14 - 9) / 22

=> x/y = 5 / 22

First fraction = 9 / 22

Second fraction = 5 / 22

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Answer:

Let the fractions be a/b and x/y

According to question

a/b + x/y = 7 / 11 ------(1)

a/b - x/y = 2 / 11 -------(2)

On adding equation 1 and 2, we get

2× a/b = ( 7 + 2) / 11

=> a/b = 9 / 22

Now,

On substituting the value of a/b in equation 1, we get

9 / 22 + x/y = 7 / 11

=> x/y = 7 / 11 - 9 / 22

=> x/y = ( 14 - 9) / 22

=> x/y = 5 / 22

First fraction = 9 / 22

Second fraction = 5 / 22

Step-by-step explanation:

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