Question

10) Write a Pythagorcun triplet whose one member is :
1) 6 ) 14 ) 8 iv) 18​

Answer 1

$\huge\mathfrak\red {★Answer★ }$

If we take m2 + 1 = 18,

m2 = 17

The value of m will not be an integer.

If we take m2 − 1 = 18, then m2 = 19

Again the value of m is not an integer.

Let 2m =18

m = 9

Thus, m2 − 1 = 81 − 1 = 80 and m2 + 1 = 81 + 1 = 82

the Pythagorean triplet is 18, 80, and 82.

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