Question

10. Write programs in java to find the sum of the following series
a) S = 1 +2²+3³+4⁴
​pls answer it

Answer 1

Required Answer:-

Given Question:

• Write a program in Java to find the sum of the series. S = 1 + 2² + 3³ + 4⁴...n^n

Approach:

This is a very simple program. Read this post and get the answer.

Here comes the program.

package com.student;

import java.util.*;

public class SeriesSum

{

public static void main(String args[])

{

/*

* S = 1 + 2^2 + 3^3... N^N

* Question^^

* Answered by @AnindyaAdhikari

*/

Scanner sc = new Scanner(System.in);

System.out.print("Enter the value of n - ");

int n=sc.nextInt();

double s = 0.0; //to store susum of the series.

for(int i=1;i<=n;i++)

s+=Math.pow(i, i);

System.out.print("Sum of the series is: "+s);

}

}

How it's solved?

At first, we will import Scanner class. Scanner class is present in utility package of Java. Now, we will create a class, main() method and objects of Scanner class. Now, we will take n as input from the user. The nextInt() method of scanner class is used to take an integer as input. Now, we will declare a variable s to store the sum of the series. Then, a loop is created that will iterate from i=1 to n. We will add each terms of the series inside the loop. (Sum = Sum + i^i). We can see that Math.pow() function is used here to calculate i raised to the power i. Each term of the series is added in this way. Time to print.

Variable Description:

• n (int):- To input the number of terms for the series sum.
• s (double):- To calculate and store the sum of the series.
• i (int):- Loop variables.

Output is attached.

Answer 2

Series:-

1¹+2²+3³+....+n^n

Logic:-

s+=i*i

• where i is a loop variable
• variable s is for storing sum

Code:-

import java.util.*;

class Code

{

public static void main (String ar [])

{

Scanner sc= new Scanner (System.in);

System.out.println("Enter a limit");

int n=sc.nextInt();

int s=0;

for(int i=1;i<=n;i++)

s+=Math.pow(i,i); /*Or u can write s=i*i;

*loop ends

*/

System.out.println("Sum="+s);

}

}