Question

10. Write the following numbers in generalised form.

(i) ab

(ii) 85

(iii) 132

(iv) 1000

11. Show that the difference of the given numbers and the numbers obtained by reversing

their digits is divisible by 9.

(i) 59

(ii) 203

12. Find the values of P and Q from the given addition problem

13. If 54x is a multiple of 3 , where x is a digit , what is the value of x?

14. If N÷5 leaves a remainder of 4, then what could be the possible values of the one’s digit

of N?

15. Check the divisibility of 2146587 by 9 using the divisibility role​

Answer 1

10) i) a*b

ii) 8*10+5*1

iii)1*100+3*10+2

iv)10*10

11) I don't know so sorry

12 ) see attached image

13) see attached image

14) If the unit digit of a number is 0 or 5, then it is divisible by 5. hence if we need the remainder of 4 then unit digit of number should be 4 or 9

15:-

Divisibility Rule of 9

The rule for divisibility by 9 is similar to divisibility rule for 3. That is, if the sum of digits of the number is divisible by 9, then the number itself is divisible by

So let's check for your given digit

So digit is 2146587 now 2+1+4+6+5+8+7 it is equal to 33 and that is not divisible by 9 so this will not be divisible by 9 it will lead answer in decimals