10(x^2-1)=3(3x^2+2) please give me better answer
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Answered by
17
Answer:
x = ± 4
Step-by-step explanation:
Given : 10(x² - 1) = 3(3x² + 2)
Multiplying each term inside the bracket with the number which is present outside the bracket.
On further solving, we get
→ 10(x²) - 10(1) = 3(3x²) + 3(2)
→ 10x² - 10 = 9x² + 6
Transposing the terms. Writing common terms together.
→ 10x² - 9x² = 6 + 10
→ x² = 16
→ x = √16
→ x = - 4 or 4
The value of x can be + 4 or - 4.
This is because if we take square of + 4, we get 16 and if we take the square of - 4, we get the number 16.
Answered by
0
Answer: 10( x^2 - 1 ) = 3( 3x^2 + 2 )
10x^2 - 10 = 9x^2 + 6 ( on multiplying )
10x^2 -9x^2 = 6 + 10 ( on transposing )
x^2 = 16
x = 4
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