Math, asked by VASU004, 10 months ago

10(x^2-1)=3(3x^2+2) please give me better answer

Answers

Answered by Anonymous
17

Answer:

x = ± 4

Step-by-step explanation:

Given : 10(x² - 1) = 3(3x² + 2)

Multiplying each term inside the bracket with the number which is present outside the bracket.

On further solving, we get

→ 10(x²) - 10(1) = 3(3x²) + 3(2)

→ 10x² - 10 = 9x² + 6

Transposing the terms. Writing common terms together.

→ 10x² - 9x² = 6 + 10

→ x² = 16

→ x = √16

x = - 4 or 4

The value of x can be + 4 or - 4.

This is because if we take square of + 4, we get 16 and if we take the square of - 4, we get the number 16.

Answered by Dragonbrains1
0

Answer: 10( x^2 - 1 ) = 3( 3x^2 + 2 )

10x^2 - 10 = 9x^2 + 6 ( on multiplying )

10x^2 -9x^2 = 6 + 10 ( on transposing )

x^2 = 16

x = 4

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