Math, asked by sanskarmohanty4, 23 hours ago

10(x−2y)^ 3 +6(x−2y)^ 2 −20(x−2y)

Answers

Answered by sorenashalata8
0

Step-by-step explanation:

10(x-2y)^3 +6(x-2y)^2-20(x-2y)

= (10x - 20y)^3+ (6x-12y)^2 - (20x -40y)

= (1000x-8000y) + (36x-144y) - (20x-40y)

= 7000xy + 108xy - 20xy

= 7088xy

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Answered by dhanusus
1

Answer:

7088xy

Step-by-step explanation:

10(x-2y)^3 +6(x-2y)^2-20(x-2y)

= (10x - 20y)^3+ (6x-12y)^2 - (20x -40y)

= (1000x-8000y) + (36x-144y) - (20x-40y)

= 7000xy + 108xy - 20x

= 7088xy

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