Question

10 - x is one of the class intervals of a frequency distribution and the class-mark of the class
interval is 16. Then the upper boundary x is equal to:
(a) 22
(b) 26
(c) 13
(d) 20​

Answer 1

Answer:

djxjdjxj ;+"! ₹+₹! ;-₹+#9+#:₹;₹(

Answer 2

Answer:

(b) 26

Step-by-step explanation:

Class Interval = 16

U is Upper Limit

L is Lower Limit

U - L = 16

U - (10-x) = 16

U - 10+x = 16

U = 16+10-x

U = 26-x