(10/ (x+y)) + (2/ (x-y)) = 0, (15/ (x+y)) - (5/ (x-y)) = 2 find x and y.
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Take (1/x+y) = a, and (1/x-y) = b
From here, we get the equations,
10a + 2b = 0, and 15a - 5b = 2
Solving these, we get,
a = 1/20, and b = -1/4
Now we have the equations,
x + y = 20, and x - y = -4
Again, solving them, we finally get,
x = 8, and y = 12
Hope this helps. Peace.
From here, we get the equations,
10a + 2b = 0, and 15a - 5b = 2
Solving these, we get,
a = 1/20, and b = -1/4
Now we have the equations,
x + y = 20, and x - y = -4
Again, solving them, we finally get,
x = 8, and y = 12
Hope this helps. Peace.
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Thank you also......very much
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the above images will be the best solution for you
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Friend what will be the answer if: 1. The first equation remains same .. 2.The Second Equation also remain same but its constant value that is 2 may change to -2 . Else nothing will change
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