Question

10/x+y +2/x-y=4;15/x+y-5/x-y=-2 plzz solve this simultaneous equation

Answer 1

10/x+y +2/x-y=4________(1)
15/x+y-5/x-y=-2________(2)
let 1/x+y=A and 1/x-y=Bua
therefore eqn 1 and 2 will become
10A+2B=4
15A-5B=-2

Now multiplying eqn 1 by -5 and eqn 2 by 2 we get
-50A-10B=-20
30A-10B=-4
Now by elimination method we have A=16/80=1/5
and B=1
but 1/x+y=A and 1/x-y =B
putting the values of A and B we get x+y=5____(3) and x-y=1______(4)
Now from eqn 3 we get x=5-y Now putting the value of x in eqn 4 we get y=2 and x=5-y i.e x=5-2=3. Therefore x=3 and y=2
_______x________x__________x________

Answer 2

hey heres ur answer in the attachment
hope it helps u ....... : )
just one min solving
its a gr8 mess but i hope u understand it...❤❤