Math, asked by shanthi2468, 10 months ago

10. X#Y=(x3-Y3)
X%Y=(X-Y)
X@Y=X/Y
XIY=X*Y
Determine the value of (8@2%2)!(2#3)
a. -76
b. 38
c. 1
di o​

Answers

Answered by jacobpankavil
1

Answer:

(8/2-2)×(2³-3³)

(4-2)×(8-27)

2×-19

=-38

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