Question

(10 x²+ 5x-3) + (7x²- 2x + 7)

Answer 1

(10 x²+ 5x-3) + (7x²- 2x + 7)

= 10 x²+ 5x-3+ 7x²- 2x + 7

=17x²+3x+4

Answer 2

$\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

= (10x²+5x-3)+(7x²-2x+7)

= 10x²+5x-3+7x²-2x+7

{By opening brackets}

= 10x²+7x²+5x-2x-3+7

{By rearranging}

= 17x²+3x+4.

Solution of this are not real because here Discriminant <0.

=》 Discriminant (D) = b²-4ac

= (3)² - 4(4)(17)

= 9 - 4(64)

=9 - 256

= -247<0.

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST.

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