10(y+3)+5=60
find the value by the process of both sides variable and constant.....
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10y+30+5=60
10y=60-30-5
10y=25
y=25/10
y=5/2
10y=60-30-5
10y=25
y=25/10
y=5/2
Answered by
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(y+3)+5=60-10
y+3+5=50
y+3=50-5
y+3=45
y=45-3
y=42
y+3+5=50
y+3=50-5
y+3=45
y=45-3
y=42
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