Math, asked by santoshkumar88538853, 6 months ago

10. यदि y = bsin.x+acos.x, तब सिद्ध कीजिये किd2y/dx2+y=0

Answers

Answered by amitsnh

0

Answer:

y = bsinx + acosx

dy/dx = bcosx - asinx

d2y/dx2 = -bsinx - acosx

d2y/dx2 = -(bsinx + acosx)

d2y/dx2 = -y

d2y/dx2 + y = 0

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