10 year ago A was one third of q's age if the ratio of the present age of a and q is 4 is to 7 what is the total sum of the ages after 5 years?
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Answered by
32
Answer:
54
Step-by-step explanation:
Ratio of present age
a / q = 4 / 7
a = 4q/7
10 yrs ago:
(a - 10) = (1/3) × (q - 10)
4q/7 - 10 = q/3 - 10/3
4q/7 - q/3 = 10 - 10/3
(4q/7 × 3/3) - (q/3 × 7/7) = (10 × 3/3) - 10/3
12q/21 - 7q/21 = 30/3 - 10/3
5q/21 = 20/3
q = 20/3 × 21/5
q = 28
If q = 28 then
a = 4q/7
= (4 × 28)/7
= 16
After 5 years:
Sum of ages = (a + 5) + (q + 5)
= 16 + 5 + 28 + 5
= 54
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