10 year ago father was 12 times as old as his son and 10 years hence he will be twice as old as his son will we find the present age
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12(x-10)=y-10 ............a
2(×+10)=y+10...............b
solve these eqN you will get answer
2(×+10)=y+10...............b
solve these eqN you will get answer
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