Question

10 year ago the age of a father was four time of his son. 10 year hence the age of the father will be twice that of his son. the present age of the father and the son are.​

Answer 1

Answer:

The father's age 10 years ago was 4 times the age of his son, and in the present time (10 years later) he will be 8 times older than his son

Father's age is 50

and sons age is 20

Step-by-step explanation:

Take father's age as Y

Sons age as X

10 years ago = X - 10 and Y - 10

4(x - 10) = Y - 10

4x - 10 = Y - 10

4x - 40 = Y - 10

y = 4x - 30 - 10

or 4x - Y = 30

After 10 Years, X + 10 and Y + 10

2(x + 10) = Y + 10

Y = 2x + 10

4x - 30 = 2x + 10

4x - 2x = 30 + 10

2x = 40

X = 20

Subtitling x in y = 2x + 10

Y = 50