Math, asked by shadmaashadma5186, 1 year ago

10 year ago the age of father was four time of his son ten years hence the age of the father will be twice that of his son. The present age of the father and son.

Answers

Answered by Masudsarkar93
0
4x+20=2(x+20)
or, x=10
so, 10 years ago son's age was x=10
10 year ago father age was 4x=4×10=40
therefore, The present age of son is, (10+10+10)=30
The present age of the father is (40+10+10)=60
Hope it helps you.
Answered by PixleyPanda
1

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20

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