Question

10 year ago the age of father was four time of his son10 year hence the age of father will be twice that of his son find the present age of father and son

Answer 1

let the age of father be x
and age of son be y
10 years ago age of father = x-10
age of son = y-10
ATQ
x-10=4(y-10)
x-10 = 4y-40
x-4y=-40+10
x-4y = -30 .......(1)

10 years hence
age of father=x+10
age of son = y+10
ATQ
x+10=2(y+10)
x+10=2y+20
x-2y= 20 -10
x-2y= 10 ......(2)
by elimination method,
x-4y=-30
x-2y=10
- + -
________
-2y=-20
y=10
so, x=30

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20