Question

10 years age the age of father was 4.
time then age of his son 10 years hence the father is twice on the present
age to son​

Answer 1

Answer:

45 year jdhdudur7r77e7r7e7e7r7r

Answer 2

Answer:

Let the present age of father be x

and the present age of son be y

According to the question

x-10=4(y-10) (equation 1)

x+10=2(y+10) (equation 2)

Solve the first equation:-

x-10=4(y-10)

x-10=4y-40

x-4y=-40+10

x-4y=-30

x=-30+4y (equation 3)

Solve the second equation:-

x+10=2(y+10)

x+10=2y+20

x-2y=20-10

x-2y=10 (equation 4)

Putting the equation 3 into equation 4

(-30+4y)-2y=10

-30+4y-2y=10

2y=10+30

2y=40

y=40/2 =20

x=-30+4y

x=-30+4×20

×=-30+80

×=50

So,

The present age of father be 50 years

and the present age of son be 20 years.