Question

10 years ago a father was 6times as old as his daughter. After 10years he will be twice as old as his daughter. Determine their present age
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Answer 1

Step-by-step explanation:

Let the current age of daughter be x

So daughter's age after 10 years would be x10 years

Father's age after 10 years would be 2(x+10)

Daughter's age 10 years ago was x-10 years

Father's age 10 years ago was 6(x -10)

now Father's age 10years ago (Father's age after 10 years from now)-20

putting value in equation 6(x-10)

2(x+10) -20 6x-60 2x +20-20 6x-2x 60 x 60/4 15

So father's current age is 2(x+10) -10 2(15+10) -10 40

father's current age 40 Years