Question

10 years ago A was 1/3d of Q,s age if
the ratio of the present ages of A and Q is
4:7, What is the total sum of their ages
after
?
five years​

Answer 1

Answer:

Sum of age of aa and qq after 5 years is 54 years

Step-by-step explanation:

Let the present age of aa be 4x

Let the present age of qq be 7x

Age of aa 10 years ago =4x - 10=4x−10 years

Age of qq 10 years ago =7x - 10=7x−10 years

Given that 10 years ago, a was \frac{1}{3}

3

1

of q's age

\begin{gathered}4x - 10 = \frac{1}{3} \times (\,7x - 10)\,\\\\ 3 \times (\,4x - 10)\, = 7x - 10\\\\ 12x - 30 = 7x - 10\\\\ 12x - 7x = -10 + 30\\\\ 5x = 20\\\\ x = 4\end{gathered}

4x−10=

3

1

×(7x−10)

3×(4x−10)=7x−10

12x−30=7x−10

12x−7x=−10+30

5x=20

x=4

Thus, present age of aa = 4 \times 4 = 16\hspace{0.1cm}years=4×4=16years

Present age of qq = 7 \times 4 = 28\hspace{0.1cm}years=7×4=28years

Age of aa after 5 years =5 + 16 = 21\hspace{0.1cm}years=5+16=21years

Age of qq after 5 years =5 + 28 = 33\hspace{0.1cm}years=5+28=33years

Thus, Sum of age of aa and qq after 5 years = 21 + 33 = 54\hspace{0.1cm}years=21+33=54years