Question

10 years ago a was half of b in age if the ratio of their present ages is 3 is 24 what will be the total of their present ages

Answer 1

i think the answer is 12

Answer 2

Let A's age 10 years ago = x years. 
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4 
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10) 
= (3x + 20) = 35 years.