Question

10 years ago, age of farid was thrice the age of his daughter. 10 years hence, farid's age will be twice that of
his daughter. Their present ages are in the ratio of:

Answer 1

Answer:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+10)+10=2[(x+10)+10]

⇒3x+20=2x+40

⇒x=20

∴ Required ratio =(3x+10):(x+10)=70:30=7:3

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